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The function f satisfies f(sqrt{x+1}) = 1/x for all x > or = to -1, x =/= 0. Find f(2).

 

I already tried 1/2 and sqrt{3}/3

 Apr 5, 2019
edited by ANotSmartPerson  Apr 5, 2019
edited by ANotSmartPerson  Apr 5, 2019
edited by ANotSmartPerson  Apr 5, 2019
edited by ANotSmartPerson  Apr 5, 2019
edited by ANotSmartPerson  Apr 6, 2019
 #1
avatar+105879 
+1

Why don't you get rid of all those unnecessay $ signs so that your post can be easily read ?

 Apr 5, 2019
 #2
avatar+279 
0

Ok I fixed it, sorry about that. ):

 Apr 5, 2019
 #3
avatar+105879 
0

Yea but it is still not very readable....

 

If you stuck that LaTex, the stuff that was contained between the dollar signs, in a LaTex box (you can find the LaTex icon in the ribbon)

then maybe it would display properly.

 

Failing that, you could just type it in normally.  And not copy it at all.

Melody  Apr 6, 2019
 #4
avatar+105879 
+2

ok, I will answer.   wink

f(sqrt{x+1}) = 1/x for all x > or = to -1, x =/= 0. Find f(2).

 

\(f(\sqrt{x+1}) = 1/x\;\; for\;\; all\;\;x\ge -1,\quad x \ne 0. \\ Find \;f(2).\\ 2=\sqrt{x+1}\\ 4=x+1\\ 3=x\\ x=3\\ f(\sqrt{3+1}) = 1/3\\ f(2)=1/3\)

.
 Apr 6, 2019
 #5
avatar+279 
+1

Thanks Melody, sorry for the trouble..

 Apr 7, 2019

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