In triangle ABC, altitudes AD, BE, and CF intersect at the orthocenter H. If angle ABC = 49 and angle ACB = 12, then find the measure of BHC, in degrees.
We have that angle ABC=49, and that ACB=12, so we can see that BAC=119. FHE=BHE and we can find FHE by calculating the angle degrees in FHEA, by doing 360−90(AFH)−90(AEH)−119(FAE)=61=FHE=BHC, so your answer would be 61.
We have that angle ABC=49, and that ACB=12, so we can see that BAC=119. FHE=BHE and we can find FHE by calculating the angle degrees in FHEA, by doing 360−90(AFH)−90(AEH)−119(FAE)=61=FHE=BHC, so your answer would be 61.
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