If \(f(x)=\frac{x+4}{x^2+ax+b}\) and \(f(x)\) has two vertical asymptotes at \(x=1\) and \(x=-2\), find the sum of \(a\) and \(b\).
x + 4
__________
x^2 + ax + b
If the vertical asymptotes are x =1 and x = -2....the denominator is
( x - 1) ( x + 2) = x^2 + x - 2
So.....
a = 1 and b = -2
So....a + b = 1 + (-2) = -1
+145 
