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Find x, given that\(\dfrac{\sqrt{x}}{x\sqrt{3}+\sqrt{2}} = \dfrac{1}{2x\sqrt{6}+4}.\) I tried to cross mutiply but I didn't get anywher from that. I solved it 

 Apr 8, 2022
edited by Guest  Apr 8, 2022
edited by Guest  Apr 8, 2022
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x = 1/4.

 Apr 8, 2022

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