+0  
 
0
221
1
avatar

he equation y = -16t^2 + 80t describes the height (in feet) of a projectile launched from the ground at 80 feet per second. At what $t$ will the projectile reach 36 feet in height for the first time? Express your answer as a decimal rounded to the nearest tenth.

 May 21, 2019
 #1
avatar+19914 
-1

Substitute   y = 36

 

36 = -16t^2+80 t      now solve for t

16t^2-80t + 36 = 0        use quadratic formula...you will find 2 values for t....one will be the popint it is rising (the first time it reaches 36 ft) and the other will be when it is coming back down

 

Quadratic formula   a = 16     b = - 80   c = 36

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

.
 May 21, 2019

19 Online Users

avatar