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#1**0 **

C) You have to use your iterative algorithm about 6 times to get the accuracy of 3 decimal places as follows:

(5, -2.92, -2.765434415, -2.738480987, -2.733307664, -2.732297173)

So, -2.732 is ONLY one solution to your equation. There are two more: x= - 1 and x =sqrt(3) - 1, which you cannot get by using the iterative algorithm.

5) This is also an iterative algorithm. Using it 4 times gives the following results:

2016 = 50 tadpoles

2017 = 57 tadpoles

2018 = 64 tadpoles

2019 = 72 tadpoles

2020 = 79 tadpoles.

Guest Nov 3, 2018

edited by
Guest
Nov 3, 2018

#1**0 **

Best Answer

C) You have to use your iterative algorithm about 6 times to get the accuracy of 3 decimal places as follows:

(5, -2.92, -2.765434415, -2.738480987, -2.733307664, -2.732297173)

So, -2.732 is ONLY one solution to your equation. There are two more: x= - 1 and x =sqrt(3) - 1, which you cannot get by using the iterative algorithm.

5) This is also an iterative algorithm. Using it 4 times gives the following results:

2016 = 50 tadpoles

2017 = 57 tadpoles

2018 = 64 tadpoles

2019 = 72 tadpoles

2020 = 79 tadpoles.

Guest Nov 3, 2018

edited by
Guest
Nov 3, 2018