+0  
 
0
30
1
avatar

I need help

Guest Nov 3, 2018

Best Answer 

 #1
avatar
0

C)    You have to use your iterative algorithm about 6 times to get the accuracy of 3 decimal places as follows:

(5, -2.92, -2.765434415, -2.738480987, -2.733307664, -2.732297173)

So, -2.732 is ONLY one solution to your equation. There are two more: x= - 1 and x =sqrt(3) - 1, which you cannot get by using the iterative algorithm.

 

5) This is also an iterative algorithm. Using it 4 times gives the following results:

2016 = 50 tadpoles

2017 = 57 tadpoles

2018 = 64 tadpoles

2019 = 72 tadpoles

2020 = 79 tadpoles.

Guest Nov 3, 2018
edited by Guest  Nov 3, 2018
 #1
avatar
0
Best Answer

C)    You have to use your iterative algorithm about 6 times to get the accuracy of 3 decimal places as follows:

(5, -2.92, -2.765434415, -2.738480987, -2.733307664, -2.732297173)

So, -2.732 is ONLY one solution to your equation. There are two more: x= - 1 and x =sqrt(3) - 1, which you cannot get by using the iterative algorithm.

 

5) This is also an iterative algorithm. Using it 4 times gives the following results:

2016 = 50 tadpoles

2017 = 57 tadpoles

2018 = 64 tadpoles

2019 = 72 tadpoles

2020 = 79 tadpoles.

Guest Nov 3, 2018
edited by Guest  Nov 3, 2018

35 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.