C) You have to use your iterative algorithm about 6 times to get the accuracy of 3 decimal places as follows:
(5, -2.92, -2.765434415, -2.738480987, -2.733307664, -2.732297173)
So, -2.732 is ONLY one solution to your equation. There are two more: x= - 1 and x =sqrt(3) - 1, which you cannot get by using the iterative algorithm.
5) This is also an iterative algorithm. Using it 4 times gives the following results:
2016 = 50 tadpoles
2017 = 57 tadpoles
2018 = 64 tadpoles
2019 = 72 tadpoles
2020 = 79 tadpoles.
C) You have to use your iterative algorithm about 6 times to get the accuracy of 3 decimal places as follows:
(5, -2.92, -2.765434415, -2.738480987, -2.733307664, -2.732297173)
So, -2.732 is ONLY one solution to your equation. There are two more: x= - 1 and x =sqrt(3) - 1, which you cannot get by using the iterative algorithm.
5) This is also an iterative algorithm. Using it 4 times gives the following results:
2016 = 50 tadpoles
2017 = 57 tadpoles
2018 = 64 tadpoles
2019 = 72 tadpoles
2020 = 79 tadpoles.