+0  
 
+1
134
1
avatar+157 

If  \(a_0 = \sin^2 \left( \frac{\pi}{45} \right)\) and \(a_{n + 1} = 4a_n (1 - a_n)\)
for \(n \ge 0,\) find the smallest positive integer \(n\) such that \(a_n = a_0.\)

 Apr 1, 2020
 #1
avatar+21957 
+1

Using my calculator, I got a9 = a0.

 Apr 1, 2020

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