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Assuming that the birth of a boy or a girl is equally likely, what is the probability that the three children in a family include at least one boy and one girl? Express your answer as a common fraction.

 Nov 11, 2019
 #1
avatar+22114 
+2

I believe this has been answered before.....but I'll try anew:

1=boy  0=girl

possibities

111

110

101

011

100

010

001

000      6 out of 8 include at least 1 boy 1 girl    6/8 = 3/4

 Nov 11, 2019
 #2
avatar+109740 
+1

EP is correct

 

We have 2 * 2 * 2  =   2^3  =  8 possibilities

 

Only  two of these  are either all boys or all girls

 

So

 

[ 8 - 2  ] / 8   =

 

6 / 8  =

 

3 / 4

 

 

cool cool cool

CPhill  Nov 11, 2019

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