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log(2)(y+2)-log(2)(y-2)=1
 Aug 1, 2013
 #1
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log(2)(y+2)-log(2)(y-2)=1 => log(2)[(y + 2)/(y - 2)] = log(2)2 => (y + 2)/(y - 2) = 2, (y + 2)/(y - 2) > 0, y isn't equal to 2. The rest of solution should be easy (we transformed into the algebraic equation here).
 Aug 2, 2013
 #2
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log(2)*(y+2)-log(2)*(y-2) = log(2)*[(y+2)-(y-2)] = log(2)*[y+2-y+2] = log(2)*4 = 1.20... != 1
 Aug 2, 2013

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