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A circle passes through (-1,6) and has a center at (2,3). The equation of the circle can be written as x^2 + y^2 + jx + ky + l = 0. What is j*k*l?

 Jul 27, 2020
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Using the distance formula, the radius is √(2-(-1))^2 + (3-6)^2 = √3^2 + 3^2 = √18. The equation is shown as (x -2)^2 + (y-3)^2 = 18. If we expand this, we get x^2 - 4x + y^2 - 6y + 9 - 18 + 4 = 0 which is is x^2 + y^2 - 4x - 6y - 5 = 0. So j*k*l = -4* -6* -5= -120.

 Jul 27, 2020

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