We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
51
2
avatar

On a particular day in Salt Lake, UT, the temperature was given by $-t^2 +12t+50$ where $t$ is the time in hours past noon. What is the largest $t$ value at which the temperature was exactly 77 degrees?

 Jun 9, 2019
 #1
avatar+101871 
+2

We need to solve this

 

-t^2 + 12t + 50  = 77     subtract 77 from both sides

-t^2 + 12t - 27 = 0        multiply through by -1

 

t^2 - 12t + 27  = 0

 

Factor

 

(t -9) ( t -3)  = 0

 

Set each factor to 0  and solve for t

 

t - 9  = 0           t - 3  = 0

t =9                     t = 3  

 

So....9 hours past noon  =  9 PM

 

cool cool cool

 Jun 9, 2019
 #2
avatar
+1

Thank you so much! It makes sense how you did it!

 Jun 9, 2019

15 Online Users

avatar
avatar