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If \(z = \frac{ \left\{ \sqrt{3} \right\}^2 - 2 \left\{ \sqrt{2} \right\}^2 }{ \left\{ \sqrt{3} \right\} - 2 \left\{ \sqrt{2} \right\} }\)

find \(\lfloor z \rfloor\)

 Jun 25, 2019
 #1
avatar+187 
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nevermind I figured it out

 Jun 25, 2019
 #2
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actually I think I didnt lol

Mathgenius  Jun 25, 2019

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