+0  
 
-1
856
2
avatar+187 

If \(z = \frac{ \left\{ \sqrt{3} \right\}^2 - 2 \left\{ \sqrt{2} \right\}^2 }{ \left\{ \sqrt{3} \right\} - 2 \left\{ \sqrt{2} \right\} }\)

find \(\lfloor z \rfloor\)

 Jun 25, 2019
 #1
avatar+187 
+1

nevermind I figured it out

 Jun 25, 2019
 #2
avatar+187 
0

actually I think I didnt lol

Mathgenius  Jun 25, 2019

3 Online Users

avatar
avatar