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\(Given that $a(a+2b) = \frac{104}3$, $b(b+2c) = \frac{7}{9}$, and $c(c+2a) = -7$, find $|a+b+c|$.\)

 Jul 21, 2018
 #1
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There are many solutions. One of them is:

a = 4, b = 7/3, c = -1, so:

a + b + c = 4 + 7/3 + (-1) = 16/3 =5 1/3

 Jul 22, 2018

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