+0  
 
0
115
1
avatar+164 

GIven the system of equations, 

xy= 6 - 2x - 3y
yz= 6 - 4y - 2z
xz= 30 - 4x - 3z

find the positive solution for x

 Jul 5, 2018
 #1
avatar
+1

xy= 6 - 2x - 3y................(1) 

 yz= 6 - 4y - 2z...............(2)                                                                                                                                     
xz= 30 - 4x - 3z..............(3)
From (3) above:
z = (30 - 4 x)/(x + 3)
Sub z into (2) above
y(30 - 4 x)/(x + 3)= 6 - 4y - 2[(30 - 4 x)/(x + 3)]...........(4)
xy= 6 - 2x - 3y..............(1), solve for x, y in (1) and (4)
x = - 9 and y = -4, or:
x = 3  and y = 0
Sub x values into (3) above:
z = 3 and z = -11  

 Jul 5, 2018

9 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.