+586 GIven the system of equations,
xy= 6 - 2x - 3y
yz= 6 - 4y - 2z
xz= 30 - 4x - 3z
find the positive solution for x
xy= 6 - 2x - 3y................(1)
yz= 6 - 4y - 2z...............(2)
xz= 30 - 4x - 3z..............(3)
From (3) above:
z = (30 - 4 x)/(x + 3)
Sub z into (2) above
y(30 - 4 x)/(x + 3)= 6 - 4y - 2[(30 - 4 x)/(x + 3)]...........(4)
xy= 6 - 2x - 3y..............(1), solve for x, y in (1) and (4)
x = - 9 and y = -4, or:
x = 3 and y = 0
Sub x values into (3) above:
z = 3 and z = -11
