Given the equation a+b = 30 , where a and b are positive integers, how many distinct ordered-pair solutions (a,b) exist?
For a + b = n
The number of ordered-pair solutions = n - 1
So .......30 - 1 = 29
To see this.....consider something more simple
Let a + b = 10
Solutions are
1 9
2 8
3 7
4 6
5 5
6 4
7 3
8 2
9 1
The number of of solutions = 10 - 1 = 9
it wrong
sorry i made a mistake not u
