The function \(y=\frac{x^3+8x^2+21x+18}{x+2}\) can be simplified into the function y=Ax^2+Bx+C with a point of discontinuity at x=D. What is the sum of the values of A, B, C, and D?
+36916 From the given equation x cannot equal -2 (that would result in a zero denominator) so D= -2
If yo do the division of this fraction you wind up with x^2+6x+9 A = 1 B = 6 C = 9 and D = -2
I think you an take it from here.....
