Two men starting at a point on a circular 1-mile race track walk in opposite directions with uniform speeds and meet in 6 minutes, but if they walk in the same direction, it requires one hr for the faster walker to gain a lap. What is the rate of the slower walker?
+36915 Since they are going in opposite directions, when they meet they have covered 1 mile using their combined speeds x+ y mi/min
x+y mi / min * 6 min = 1 mile (x+y) * 6 = 1 or 6x + 6y =1
let x = faster y = slower
x mi /min * 60 min = y mi/min * 60 min + 1 mi or 60 x = 60 y + 1
Now you have two equations with two unknowns....solve for x and y
