Two men starting at a point on a circular 1-mile race track walk in opposite directions with uniform speeds and meet in 6 minutes, but if they walk in the same direction, it requires one hr for the faster walker to gain a lap. What is the rate of the slower walker?

Guest Feb 28, 2020

#1**+1 **

Since they are going in opposite directions, when they meet they have covered 1 mile using their combined speeds x+ y mi/min

x+y mi / min * 6 min = 1 mile (x+y) * 6 = 1 or 6x + 6y =1

let x = faster y = slower

x mi /min * 60 min = y mi/min * 60 min + 1 mi or 60 x = 60 y + 1

Now you have two equations with two unknowns....solve for x and y

ElectricPavlov Feb 28, 2020