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In acute triangle ABC, AB = c, BC = a, CA = b, and ac = 2b.  Find the numerical value of cos(A)/a + cos(C)/c.

 Dec 24, 2019
 #1
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Let the side lengths of the triangle ABC  be:  a=1,  c=1,  and  b= ac/2 = 0.5

cos(A) /a + cos(C)/c=(cos75.522°/1)+(cos75.522°/1) = 0.25 + 0.25 = 0.5 indecision

 Dec 25, 2019
edited by Dragan  Dec 25, 2019
 #2
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What makes you think it is an isosceles triangle? How about sides a = 3, side b= 6 and side c = 4

Yoy still have: a x c =2b =3 x 4 = 2 x 6 ??

 Dec 25, 2019
 #3
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Do all 3 sides have to be different in length? indecision

Guest Dec 25, 2019

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