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Given that m = 999...9 (2001 nines) and n = 888...8 (2001 eights), find the sum of the digits in the product mn.

 Jun 2, 2020
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Here is the summary of the sum of the DIGITS of the product of 2001 "8s"   x   2001  "9s"

 

Total Sum = 18009
Total Num = 4002
Total 8's: SUM =16,000. NUMBER=2,000
Total 7's: SUM =7. NUMBER =1
Total 2's: SUM =2. NUMBER =1
Total 1's: SUM =2,000. NUMBER=2,000

 Jun 2, 2020

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