If x and y are numbers such that 9^x-4^y=10 and 3^x-2^y=2, compute $3^x+2^y$.
If x and y are numbers such that 9^x-4^y=10 and 3^x-2^y=2, compute $3^x+2^y$
We can factor 9^x - 4^y as (3^x - 2^y) (3^x + 2^y)
So
(3^x - 2^y) (3^x + 2^y) = 10
( 2) ( 3^x + 2^y) = 10 divide both sides by 2
3^x + 2^y = 5
