A rock is thrown upward with a velocity of 22 meters per second from the top of a 23 meter high cliff, and it misses the cliff on the way back down. When will the rock be 10 meters from ground level?
A rock is thrown upward with a velocity of 22 meters per second from the top of a 23 meter high cliff, and it misses the cliff on the way back down. When will the rock be 10 meters from ground level?
xf = x0 + vo t + 1/2 a t^2 xf = 10 m x0 = 23 m vo = 22 m/s a = - 9.9 m/s^2
10 = 23 + 22 t - 4.9 t^2
0 = - 4.9t2 + 22t + 13 Use quadratic formula to find t = 5.02 s and - .529 s (throw out)