Coin A is tossed three times and coin B is tossed two times. What is the probability that more heads are tossed using coin A than using coin B? Express your answer as a common fraction.
+128474 We have 2^3 * 2^2 = 32 outcomes
The ones where Coin A has more heads outcomes than Coin B are
A B
HHH HH = 1* 1 = 1 way
HHH TH = 1 * 2 = 2 ways
HHH TT = 1 * 1 = 1 way
HHT HT = 3 * 2 = 6 ways
HHT TT = 3 * 1 = 3 ways
HTT TT = 3 * 1 = 3 ways
So....the total ways = 16
So....the probability = 16 / 32 = 1 / 2
