The sum of the first terms of a certain sequence is \(n(n + 1)(n + 2)\). Find the tenth term of the sequence.
\(\text{let }s_n = \sum \limits_{k=1}^n~a_k = n(n+1)(n+2)\\ s_{10}=s_9+a_{10}\\ a_{10} = s_{10}-s_9 = (10)(11)(12) - (9)(10)(11) = 330\)
