#1**+2 **

Use pythagorean theorem to find the third side of the SMALLER triangle first.....

Then use the pythagorean theorem to find the hypotenuse of the LARGER triangle

Let me know what you find......

Well...I came up with a different answer than KeyLimePi......

Smaller triangle side.....

1^2 +s^2 = 25

s=sqrt24

Then using the Pythag theorem on the larger triangle: sqrt(24)^2 + 5^2 = Hyp^2

24 + 25 = hyp^2

49= hyp^2

7=? on the larger triangle

ElectricPavlov Mar 31, 2019

#2**+2 **

Use pythagorean theorem to find the side of the smaller triangle.

\(1^2+b^2=5^2\)

\(b=2\sqrt6\)

So continuing with the pythagorean thereom \(2\sqrt{6}^2+5^2=c^2\)

\(c=\sqrt{37}\)

I am assuming the problem asks for a square root version.

Yes I now realize my mistake. If you look in the beginning of my answer you see that I used \(5\) instead of \(5^2\)

Here is my edited answer...

Use pythagorean theorem to find the side of the smaller triangle.

\(1^2=b^2=5^2\)

\(1+b^2=25\)

\(b^2=24\)

\(b=\sqrt{24}\)

So continuing with the pythagorean thereom \(\sqrt{24}^2+5^2=c^2\)

\(24+25=c^2\)

\(24+25=49\)

\(\sqrt{49}=7\)

Therefore the answer is \(7\)

Thanks, ElectricPalov and SoulSlayer615 for correcting my previous error,

\(\pi\)

KeyLimePi Mar 31, 2019