If a sample of carbon-14 has a mass of 400 grams at time zero,how much carbon-14 will remain after 22,920 years.
C(14) = 400 x 2^-(22,920/5,730)
C(14) = 400 x 2^-4
C(14) = 400 x 0.0625
C(14) = 25 grams of Carbon 14 remains after 22,920 years.
