We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

If the object's average speed is 2.4 m/s, find the distance traveled during the second time interval.

Guest Oct 25, 2017

#1**+1 **

Okay so this is a simple multiplication problem (for the most part).

If a runner is running at 2.4 m/s what is the distance it will travel in lets say 2 minutes. <----Second time interval

Well first you'd want to convert those minutes into seconds. So there are 120 seconds in 2 minutes.

Now into the multiplication, if for every second the runner is running 2.4 meters then you would multpily 2.4 by however many seconds

(2.4) x 120 = 288 meters

MicahSmith07 Oct 25, 2017

#1**+1 **

Best Answer

Okay so this is a simple multiplication problem (for the most part).

If a runner is running at 2.4 m/s what is the distance it will travel in lets say 2 minutes. <----Second time interval

Well first you'd want to convert those minutes into seconds. So there are 120 seconds in 2 minutes.

Now into the multiplication, if for every second the runner is running 2.4 meters then you would multpily 2.4 by however many seconds

(2.4) x 120 = 288 meters

MicahSmith07 Oct 25, 2017