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Given that ∠ABD = 76°, which equation could be used to solve problems involving the relationships between ∠DBC and ∠ABC?

 Feb 24, 2020
 #1
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If BC is a ray in the interior of angle(ABD), then:

angle(ABC) + angle(CBD)  =  76o

angle(ABC)  =  76o - angle(CBD)

angle(CBD)  =  76o - angle(ABC).

 Feb 24, 2020

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