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Let $f(x)=\left(\frac37\right)^x$ be a function that is defined on the domain $[0,\infty)$. Find the range of the function.

 Mar 15, 2018
 #1
avatar+18293 
+1

The LaTex isn't displaying clearly for me...if you  have (3/7)^x   as the equation...

at x = 0 the value of f(x) = 1    (i.e. y=1)      as x becomes larger and larger the equation becomes smaller and smaller.....reaching essentially y=0

So for the domain x = 0 to infinity the range is 1 to 0   .

Here is a graph:  (disregard portion of the graph left of y-axis)

 Mar 15, 2018
edited by ElectricPavlov  Mar 15, 2018
 #2
avatar+100783 
+1

Let   \(f(x)=\left(\frac37\right)^x\)     be a function that is defined on the domain \([0,\infty)\). Find the range of the function.

 

f(0)=1     f(infinity)=+0      all the other values in the given domain are between these  so

 

 

range (0,1]

 Mar 15, 2018

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