Let $f(x)=\left(\frac37\right)^x$ be a function that is defined on the domain $[0,\infty)$. Find the range of the function.

Guest Mar 15, 2018

#1**+1 **

The LaTex isn't displaying clearly for me...if you have (3/7)^x as the equation...

at x = 0 the value of f(x) = 1 (i.e. y=1) as x becomes larger and larger the equation becomes smaller and smaller.....reaching essentially y=0

So for the domain x = 0 to infinity the range is 1 to 0 .

Here is a graph: (disregard portion of the graph left of y-axis)

ElectricPavlov Mar 15, 2018