This simplifies to (x - 1)^2 / ( x + 2)
We wil have a "hole" at x = 1 ⇒ (1,0)
A vertical asymptote at x = -2
And a "slant" asymptote found as follows
x - 4
x + 2 [ x^2 - 2x + 1]
x^2 + 2x
____________________
-4x + 1
-4x - 8
_____________
Slant asymptote y = x - 4
See the graph here : https://www.desmos.com/calculator/7hyqb8rhxb