12. x^3 - 2x^2 - 5x + 6
Using synthetic division to find the remaining polynomial, we have
1 [ 1 - 2 -5 6 ]
1 -1 -6
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1 -1 -6 0
The remaining polynomial is x^2 - x - 6 which factors as
( x - 3) ( x + 2)
So....the other two roots are 3 and - 2