Triangle ABC with vertices A(-2, 0), B(1, 4) and C(-3, 2) is reflected over the y-axis to form triangle A'B'C'. What is the length of a segment drawn from C to C'?
If C is reflected over the y axis, the point C' is (3, 2)
So....the distance from C to C' is just the distance from (-3,2) to (3,2) =
√ [ ( 3 - -3)^2 + ( 2 - 2 )^2 ] =
√ [ 6^2 + 0^2 ] =
√ 36 =
6 units
+194 
