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Triangle ABC with vertices A(-2, 0), B(1, 4) and C(-3, 2) is reflected over the y-axis to form triangle A'B'C'. What is the length of a segment drawn from C to C'?

Confusedperson  Jun 24, 2018
 #1
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If  C  is reflected over the y axis, the point  C'  is  (3, 2)

 

So....the distance from  C  to C'  is just the distance  from  (-3,2)  to (3,2)  =

 

  √ [ ( 3  -  -3)^2  +  ( 2  - 2 )^2 ]   =

 

√ [ 6^2  + 0^2  ] =

 

√ 36  =

 

6 units

 

 

cool cool cool 

CPhill  Jun 24, 2018

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