There is a line that includes the point (-8, 1) and has a slope of -1/8. What is it’s equation in slope-intercept form?
(x,y)=(-8,1)
m=-1/8
y-y1=m(x-x1)
y-1=(-1/8)(x-(-8))
y-1=(-1/8)(x+8)
Hello alrawshdeh04,
Although your answer is completely correct, the question asked "Slope-Intercept form"
\(y=mx+b\)
\(y=(-\frac{1}{8})(x+8)+1\)
\(y=-\frac{1}{8}x\)
+45 
