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Let △ABC and △CDE be equilateral triangles of the same size, and angle BCD = 80∘ between them. Find the measure of angle BAD in degrees.

 

 Dec 28, 2019

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Equilateral triangles, so both angles near C are 60 degrees

   so  angle ACD = 80 + 60 = 140 degrees

       AC and CD are equal in length, so triangle ACD is isoceles

          unlabelled angle A and D are equal  180 - 140 = 40 dgrees  so A and D are 20 degrees each

             BAD = 60 - 20 = 40 degrees  

 Dec 28, 2019
 #1
avatar+19741 
0
Best Answer

Equilateral triangles, so both angles near C are 60 degrees

   so  angle ACD = 80 + 60 = 140 degrees

       AC and CD are equal in length, so triangle ACD is isoceles

          unlabelled angle A and D are equal  180 - 140 = 40 dgrees  so A and D are 20 degrees each

             BAD = 60 - 20 = 40 degrees  

ElectricPavlov Dec 28, 2019

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