+0

# help

0
189
1

Suppose we have a square with vertices at 0, -6+13i, , -19+7i ,and -13-6i. Suppose that we want to multiply these points by a single complex number a+bi to get a square with vertices 0, 8+2i, 6+10i, and -2+8i. What is (a,b)?

Jan 25, 2020
edited by Guest  Jan 25, 2020

#1
+25530
+2

Suppose we have a square
with vertices at $$(0),~ (-6+13i),~ (-19+7i) ,~~\text{and}~ (-13-6i)$$.
Suppose that we want to multiply these points
by a single complex number a+bi to get a square
with vertices $$(0),~ (8+2i),~ (6+10i),~ ~\text{and}~ (-2+8i)$$.
What is (a,b)?

I assume:

We have a black square with vertices: $$\mathbf{z =|z|e^{i\varphi}}$$

We have a blue square with vertices: $$\mathbf{w =|w|e^{i\omega}}$$

We have a single complex number: $$\mathbf{x=a+bi}$$

Formula: $$\mathbf{w = x\cdot z \qquad \text{with}\qquad x = \dfrac{|w|}{|z|}e^{i(\omega-\varphi)} }$$

$$\text{For example we set z=(-6+13i) \quad \text{and} \quad w=(8+2i) }$$

$$\begin{array}{|rcll|} \hline |z| &=& \sqrt{ \left(-6\right)^2+13^2 } \\ &=& \sqrt{36+169} \\ &=& \sqrt{205} \\ \mathbf{|z|} &=& \mathbf{14.3178210633}\\\\ |w| &=& \sqrt{8^2+2^2} \\ &=& \sqrt{68} \\ \mathbf{|w|} &=& \mathbf{8.2462112512}\\\\ \dfrac{|w|}{|z|}&=& \dfrac{8.2462112512}{14.3178210633} \\\\ \mathbf{\dfrac{|w|}{|z|}}&=& \mathbf{0.5759403763} \\ \hline \end{array}$$

$$\begin{array}{|rcll|} \hline \omega-\varphi &=& \arctan\left(\dfrac{2}{8}\right) -\arctan\left(\dfrac{13}{-6}\right) \\ &=& 14.03624346791^\circ - (180^\circ-65.2248594312^\circ) \\ &=& 14.03624346791^\circ - 114.775140569^\circ \\ \mathbf{\omega-\varphi} &=& \mathbf{-100.738897101^\circ} \\ \hline \end{array}$$

$$\begin{array}{|rcll|} \hline \mathbf{x} &=& \mathbf{\dfrac{|w|}{|z|}*e^{i(\omega-\varphi)}} \\\\ x &=& 0.5759403763*e^{i(-100.738897101^\circ)} \\\\ x &=& 0.5759403763* \Big( \cos(-100.738897101^\circ)+i*\sin(-100.738897101^\circ) \Big) \\ x &=& 0.5759403763*(-0.1863336512-0.9824865243i) \\ x &=&-0.1073170732-0.5658536585i \\\\ \mathbf{a} &=& \mathbf{-0.1073170732} \\ \mathbf{b} &=& \mathbf{-0.5658536585} \\ \hline \end{array}$$

$$(a,~b) = (-0.1073170732,~-0.5658536585)$$

Jan 25, 2020