+0  
 
+1
26
1
avatar+312 

An infinite geometric series has common ratio 1/8 and sum 60. What is the first term of the series?

 Jan 5, 2021
edited by hihihi  Jan 5, 2021

Best Answer 

 #1
avatar+312 
+1

Let the first term be a. Because the sum of the series is 60, we have 

\(60= \frac{a}{1-(1/8)} = \frac{a}{7/8} = \frac{8a}{7}.\)

Therefore, \(a=\frac{7}{8}\cdot60=\boxed{\frac{105}{2}}\).

 Jan 5, 2021
 #1
avatar+312 
+1
Best Answer

Let the first term be a. Because the sum of the series is 60, we have 

\(60= \frac{a}{1-(1/8)} = \frac{a}{7/8} = \frac{8a}{7}.\)

Therefore, \(a=\frac{7}{8}\cdot60=\boxed{\frac{105}{2}}\).

hihihi Jan 5, 2021

31 Online Users

avatar
avatar
avatar
avatar