The equation $y = -4.9t^2 - 3.5t + 2.4$ relates the height $y$ (in meters) to the elapsed time $t$ (in seconds) for a ball thrown downward at 3.5 meters per second from a height of 2.4 meters from the ground. In how many seconds will the ball hit the ground? Express your answer as a decimal rounded to the nearest hundredth.
+36916 When the ball hits the ground h = 0
so set the equation = 0 and solve for 't'
0 = -4.9t^2-3.5t + 2.4 solve for t (quadratic formula) Let me know what you find!
