Alphonse and Beauregard each roll one fair cubical die, nubmered from 1 through 6. Find the probability that Alphonse rolls a higher number than Beauregard.
There are 36 possible combinations of rolls
if B rolls a
1 there are 5 higher rolls that A could roll
2 4
3 3
4 2
5 1 5 + 4 +3 + 2 + 1 15 out of 36 combinations with A> B 15/36= 5/12
(as an aside: there will be 15 rolls where A < B and 6 will be ties 15 + 15 + 6 = 36 possible rolls)