What is the inverse of f(x)=(x+6)^2 for x≥–6 where function g is the inverse of function f?
g(x)=[√x]−6, x≥0
g(x)=[√x-6], x≥6
g(x)=[√x+6], x≥−6
g(x)=[√x] +6, x≥0
f(x) = (x + 6)^2 for x ≥ 6
For f(x)......write y
y = ( x + 6)^2 take the square root of both sides
√y = x + 6 subtract 6 from both sides and "swap" x and y
√x - 6 = y for y, write g(x)
So
g(x) = √x - 6
Since the first point on the original graph is (-6,0)
The first point on this graph is (0,-6)
So x ≥ 0