A fitness club offers a hip-hop dance class and a step-dance class. There are currently 13 people in the hip-hop class, and attendance is increasing by 9 people per month. There are currently 37 people in the step-dance class, and attendance is increasing by 6 people per month. After how many months will there be the same number of people in each class?

Guest May 31, 2017

#1**+2 **

Let's call the number of months that have passed " m " .

num. of people in hip-hop class = 13 + 9m

num. of people in step-dance class = 37 + 6m

What is " m " when num. of people in hip-hop class = num. of people in step-dance class ?

What is " m " when 13 + 9m = 37 + 6m ?

13 + 9m = 37 + 6m Subtract 6m from both sides of the equation.

13 + 3m = 37 Subtract 13 from both sides of the equation.

3m = 24 Divide both sides by 3.

m = 8

After 8 months, there will be the same number of people in each class. :)

....However.....instead of the two classes competing, maybe they should join together, like this?

hectictar
May 31, 2017

#1**+2 **

Best Answer

Let's call the number of months that have passed " m " .

num. of people in hip-hop class = 13 + 9m

num. of people in step-dance class = 37 + 6m

What is " m " when num. of people in hip-hop class = num. of people in step-dance class ?

What is " m " when 13 + 9m = 37 + 6m ?

13 + 9m = 37 + 6m Subtract 6m from both sides of the equation.

13 + 3m = 37 Subtract 13 from both sides of the equation.

3m = 24 Divide both sides by 3.

m = 8

After 8 months, there will be the same number of people in each class. :)

....However.....instead of the two classes competing, maybe they should join together, like this?

hectictar
May 31, 2017

#2**0 **

I have your answer.

Next time, plz do your homework on your own, and dont ask it at a math website! Would you like your parents or teacher or whoever gave you this problem to know you cheated? I didn't think so. Even if you arent cheating on something, you must not be very good at math if you cant solve this!

I would just find two multiples of 6 and 9 that have differences of 24. Then, add 37 to the multiple of 6 and 13 to the multiple of 9. Simple? Ask a real person next time instead of having to resort to electronics.

GET A MATH TUTOR

Guest May 31, 2017

#7**0 **

Hectiar is ** SUPER DUPER **smart!See is profile's answers and you'll be

AsadRehman
May 31, 2017

#3**+1 **

Gee, Guest....take a Valium......!!!!

Everyone isn't endowed with your superior math abilities.......

However.......until you have some famous theorem named in your honor, we'll continue to try to help the great unwashed.....

CPhill
May 31, 2017