What is the equation of a line that passes through the point (10, 5) and is perpendicular to the line whose equation is y=54x−2 ?
y = (5/4)x - 2
A perpendicular line to this will have a negative reciprocal slope = -4/5
So..we have
y = (-4/5)(x - 10) + 5
y = (-4/5)x + 8 + 5
y = (-4/5)x + 13