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What is the equation of a line that passes through the point (10, 5) and is perpendicular to the line whose equation is y=54x−2 ?

cedes  Mar 6, 2018
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y  =  (5/4)x - 2

 

A perpendicular line to this will have a negative reciprocal slope  =  -4/5

 

So..we have

 

y  =  (-4/5)(x - 10) + 5

 

y  = (-4/5)x + 8 + 5

 

y =  (-4/5)x + 13

 

 

cool cool cool

CPhill  Mar 6, 2018

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