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The sum of the squares of three consecutive positive integers is 29. Find the sum of the three integers.

 Jan 2, 2020
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We have that

 

(n - 1)^2  + n^2 +  ( n + 1)^2   = 29

 

n^2  - 2n  + 1  +  n^2  + n^2 +2n +1   =  29      simplify

 

3n^2  +  2   = 29

 

3n^2  = 27

 

n^2 =  9

 

n = 3

 

So....the three integers are    2, 3 and 4

 

And their sum  =   9

 

 

cool cool cool

 Jan 2, 2020
edited by CPhill  Jan 2, 2020

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