The sum of the squares of three consecutive positive integers is 29. Find the sum of the three integers.
We have that
(n - 1)^2 + n^2 + ( n + 1)^2 = 29
n^2 - 2n + 1 + n^2 + n^2 +2n +1 = 29 simplify
3n^2 + 2 = 29
3n^2 = 27
n^2 = 9
n = 3
So....the three integers are 2, 3 and 4
And their sum = 9