A subway car is moving a distance of (4/(3x-6)) feet every (8/(9x-18)) seconds. What is its average rate of travel in feet per second?
+37146 (4/(3x-6)) feet / (8/(9x-18)) seconds = (4* (9x-18) / (8 (3x-6)) = (36x -72)/(24x-48) = (3x-6)/(2x-4) f/s = 3/2 f/s
**edited....misread Q ****
+781 Speed= distance/time.
We plug in the given expressions for distance and time.
Speed=
\(\frac{\frac{4}{3x-6}}{\frac{8}{9x-18}}\\ =\frac{4}{3x-6}\cdot\frac{9x-18}{8}\\ =\frac{1\cdot3}{1\cdot2}\\ =\frac{3}{2}\)
This is 3/2 feet per second.
