+0

# Help!!

0
393
4
+156

I don't understand the first two. I can't find the answer.  I think the last 4 are correct but I'm not sure. Please help!

Aug 24, 2018

#1
+392
+2

For the first two, you can use Pythagorean Theorem. This states that $${a}^{2}+{b}^{2}={c}^{2}$$, where $$a$$ and $$b$$ are the legs, and $$c$$ is the hypotenuse.

Problem 1: We already have sides $$a = 10$$ and $$c = \sqrt{170}$$. We can move the formula around for it to fit this problem better. We can change it to $${b}^{2}={c}^{2}-{a}^{2}$$. When subsituting our values in, we can get $${b}^{2}={\sqrt{170}}^{2}-{10}^{2}$$. When we square both values, we can get $${b}^{2} = 170-100$$, so $${b}^{2} = 70$$. We can solve this to be $$b = \sqrt{70}$$ or $$x = \sqrt{70}$$.

Problem 2: We already have sides $$b = 5\sqrt{2}$$ and $$c = 13$$. We can move the formula around for it to fit this problem better. We can change it to $${a}^{2}={c}^{2}-{b}^{2}$$. When plugging in our values, we can get $${a}^{2} = {13}^{2} - ({5\sqrt{2})}^{2}$$. By solving this, we can get $${a}^{2} = 119$$ which equals $$a = \sqrt{119}$$ or $$x = \sqrt{119}$$.

- Daisy

Aug 24, 2018
#2
+156
+1

Thank you so much for your help!! Are the last questions correct? I worked them out but I'm not 100% sure if they are right. Sorry.

mathelp  Aug 24, 2018
#3
+10
+2