\(We know \overline {DE}\parallel \overline {BC}. Given [ADE]=9 and [CDE]=6, find [ABC].\)
ADE=9, CDE=6
ADE=15
CE=(2/3)*AE
BD=(2/3)*AD
BCD=(2/3)*ADE=10
\(\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{10}}}}}}}}\)
+4 
+49 
