Find the sum of the first 25 terms of the sequence \(1, 2, -3, 4, 5, -6, 7, 8, -9, \dots.\)
+128408 Notice that
1 + 2 - 3 = 0
4 + 5 - 6 = 3
7 + 8 - 9 = 6
So....the first 24 terms will be groups of 3 and there will be 8 of these groups
And the last group will sum to 3(8-1) = 21
So the sum of these 8 groups will be [ 0 + 21] * (8/2) = 21 * 4 = 84
And the 25th term = 25
So...the sum is
84 + 25 =
109
