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93.

P ( Having a pet  l Having a sibling)  = 

15 students have a sibling...of these 7 have a pet

So....the probability is just 7/15 ≈ 46.7%

94.

Note.......P(A or B)  = P(A) + P(B) - P(A and B)

P(ace  or 2)  = P(ace) + P(2)  - P(ace and 2)   =

                         4/52  +  4/52  -  1/52  =

                                     7 / 52

95.  P (5 or diamond)  = P(5) + P(diamond)  - P(5 and diamond) =

                                        4/52  +  13/52    -         1/52   =

                                              16/52  =

                                               4/13

96.   We have 26 black cards....2 of them are queens....so  2/26  = 1/13

97. We have 4 kings....only one is a diamond....so  1/4

98. Don't know the answer to this one, LF   ...sorry  !!!