Find the value of \(\theta\), \(0^\circ \le \theta \le 90^\circ\), such that \(\cos 5^\circ = \sin 25^\circ + \sin \theta\). (Give your answer in degrees, not radians.)
\(\cos 5^\circ = \sin 25^\circ + \sin \theta \)
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\(\theta=arcsin(cos5°-sin25°)=\color{blue}35°\)
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