In how many ways can a group of ten students be separated into two teams? (The two teams do not have to be the same size.)
+36916 Here is my guess......I will assume a team can be ONE person
10!/(1! 9!) + 10!/(2!8!) + 10!/(3!7!) + 10!/(4!6!) + 10! / (5!5!) = 10c1 + 10c2 + 10c3 + 10c4 + 10c5
I am not sure of this !!! 
