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In how many ways can a group of ten students be separated into two teams?  (The two teams do not have to be the same size.)

 May 12, 2020
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Here is my guess......I will assume a team can be ONE person

 

10!/(1! 9!)  +  10!/(2!8!)  +  10!/(3!7!)  + 10!/(4!6!)  + 10! / (5!5!)   =   10c1 + 10c2 + 10c3 + 10c4 + 10c5 

 

I am not sure of this !!!   cheeky

 May 12, 2020

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