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What are the roots of z^2 + (1 - i)z - 2 - 2i = 0?

 May 15, 2020
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Just use the quadratic formula.

The bit under the square root is a perfect square.

 

If you need help you can ask but you must show a proper contribution of your own first.

 

 

 

Please no one provide an exact answer. We should strive for this to be a teaching/help site. Not a cheat site.

 May 15, 2020
edited by Melody  May 15, 2020

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