5. A box contains 4 black shirts, 8 blue shirts, 4 black pants, and 10 blue pants. Determine the probability of randomly selecting a blue piece of clothing or a pair of pants. Use P(A or B) = P(A) + P(B) - P(A and B) to explain your answer
(a) If independent....then
P(winning and playing at home) = P(winning) *P(playing at home)....so....
0.2 = 0.25 * 0.8 ???
0.2 = 0.2 ....so.....independent
(b) P(losing and playing away) = P(losing) * P(playing away)???
0.1 = 0.7 * 0.15 ???
0.1 = 0.105.....so....not independent
Second one
P(blue or pants) = P(blue)+ P(pants) - P(blue and pants) =
18/26 + 14/26 - 10/26 =
32/26 - 10/26 =
22/26 =
11/13